1. **Stating the problem:** Calculate the value of $\log_3 2 - \log_3 18$. 2. **Formula used:** The logarithm subtraction rule states: $$\log_b A - \log_b B = \log_b \left(\frac{A}{B}\right)$$ 3. **Apply the formula:** $$\log_3 2 - \log_3 18 = \log_3 \left(\frac{2}{18}\right) = \log_3 \left(\frac{1}{9}\right)$$ 4. **Simplify the fraction:** $$\frac{2}{18} = \frac{1}{9}$$ 5. **Express $\frac{1}{9}$ as a power of 3:** $$9 = 3^2 \implies \frac{1}{9} = 3^{-2}$$ 6. **Evaluate the logarithm:** $$\log_3 \left(3^{-2}\right) = -2$$ 7. **Final answer:** The value of $\log_3 2 - \log_3 18$ is $-2$. **Answer: A. (-2)**