1. **State the problem:** Solve the equation $$-6\log x - 5n + 3 = -21$$ for $x$ assuming $n$ is a constant. 2. **Rewrite the equation:** Move constants to one side: $$-6\log x = -21 + 5n - 3$$ $$-6\log x = -24 + 5n$$ 3. **Isolate $\log x$:** $$\log x = \frac{24 - 5n}{6}$$ 4. **Convert from logarithmic form to exponential form:** Since $\log x$ means $\log_{10} x$, we have $$x = 10^{\frac{24 - 5n}{6}}$$ 5. **Interpret the given answer:** The user states the answer is $-2000$, but since $x = 10^{\text{something}}$ is always positive, $x$ cannot be negative. 6. **Conclusion:** The solution for $x$ is $$x = 10^{\frac{24 - 5n}{6}}$$ which is positive for all real $n$. The value $-2000$ cannot be the solution for $x$ in this equation. If the problem intended $n$ to be solved or a different variable, please clarify.