1. **State the problem:** We need to fill the empty cells in a 3x3 grid so that every row, column, and diagonal sums to 24.
2. **Given numbers and positions:**
- Top row: 13, 8, _
- Middle row: _, 7, _
- Bottom row: 10, 11, 9
- Draggable numbers: 10, 11, 9, 6, 5, 3
3. **Sum rule:** Each row, column, and diagonal must sum to 24.
4. **Find missing values:**
- Top row sum: $13 + 8 + x = 24 \Rightarrow x = 24 - 21 = 3$
- Middle row sum: $a + 7 + b = 24 \Rightarrow a + b = 17$
- Bottom row sum: $10 + 11 + 9 = 30$ (already 30, so bottom row must be adjusted or numbers reassigned)
Since bottom row sum is 30, but must be 24, the initial placement of 10, 11, 9 in bottom row is incorrect. We must place the draggable numbers in empty cells to satisfy all sums.
5. **Assign variables to empty cells:**
- Top row right cell: $x$
- Middle row left cell: $a$
- Middle row right cell: $b$
- Bottom row left cell: $c$
- Bottom row middle cell: $d$
- Bottom row right cell: $e$
6. **Known fixed numbers:**
- Top row left: 13
- Top row middle: 8
- Middle row middle: 7
7. **Equations from rows:**
- Row 1: $13 + 8 + x = 24 \Rightarrow x = 3$
- Row 2: $a + 7 + b = 24 \Rightarrow a + b = 17$
- Row 3: $c + d + e = 24$
8. **Equations from columns:**
- Column 1: $13 + a + c = 24 \Rightarrow a + c = 11$
- Column 2: $8 + 7 + d = 24 \Rightarrow d = 9$
- Column 3: $x + b + e = 24 \Rightarrow 3 + b + e = 24 \Rightarrow b + e = 21$
9. **Equations from diagonals:**
- Diagonal 1 (top-left to bottom-right): $13 + 7 + e = 24 \Rightarrow e = 4$
- Diagonal 2 (top-right to bottom-left): $x + 7 + c = 24 \Rightarrow 3 + 7 + c = 24 \Rightarrow c = 14$
10. **Use diagonal 1 to find $e$:** $e = 4$
11. **Use diagonal 2 to find $c$:** $c = 14$
12. **Use column 1 to find $a$:** $a + c = 11 \Rightarrow a + 14 = 11 \Rightarrow a = \cancel{11} - 14 = -3$ (impossible since numbers are positive and from draggable set)
This contradiction means the initial fixed numbers or assumptions must be reconsidered.
13. **Re-examine draggable numbers:** 10, 11, 9, 6, 5, 3
14. **Try placing 3 in top row right cell (as found):**
- Top row: 13 + 8 + 3 = 24 (correct)
15. **Place 7 in middle middle cell (given). Now assign $a$ and $b$ from remaining numbers 10, 11, 9, 6, 5:**
- $a + b = 17$
16. **Possible pairs summing to 17:** (11,6), (10,7), (9,8), but 7 and 8 are already used.
- So $a=11$, $b=6$ or $a=6$, $b=11$
17. **Assign $a=11$, $b=6$**
18. **Bottom row numbers left: 10, 9, 5**
- $c + d + e = 24$
19. **From columns:**
- Column 1: $13 + a + c = 24 \Rightarrow 13 + 11 + c = 24 \Rightarrow c = 0$ (not in draggable numbers)
Try $a=6$, $b=11$:
- Column 1: $13 + 6 + c = 24 \Rightarrow c = 5$
- Column 3: $3 + 11 + e = 24 \Rightarrow e = 10$
- Column 2: $8 + 7 + d = 24 \Rightarrow d = 9$
20. **Check bottom row sum:** $c + d + e = 5 + 9 + 10 = 24$ correct.
21. **Check diagonals:**
- Diagonal 1: $13 + 7 + e = 13 + 7 + 10 = 30$ (not 24)
- Diagonal 2: $3 + 7 + c = 3 + 7 + 5 = 15$ (not 24)
22. **Try swapping $e$ and $d$:**
- $d=10$, $e=9$
- Bottom row sum: $5 + 10 + 9 = 24$ correct
- Diagonal 1: $13 + 7 + 9 = 29$ no
- Diagonal 2: $3 + 7 + 5 = 15$ no
23. **Try swapping $c$ and $d$:**
- $c=9$, $d=5$, $e=10$
- Bottom row sum: $9 + 5 + 10 = 24$ correct
- Column 1: $13 + 6 + 9 = 28$ no
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**Final solution:**
- Top row: 13, 8, 3
- Middle row: 6, 7, 11
- Bottom row: 5, 9, 10
Check sums:
- Rows: $13+8+3=24$, $6+7+11=24$, $5+9+10=24$
- Columns: $13+6+5=24$, $8+7+9=24$, $3+11+10=24$
- Diagonals: $13+7+10=30$ (not 24), $3+7+5=15$ (not 24)
Since diagonals do not sum to 24, the problem as stated with given numbers and draggable numbers cannot satisfy all conditions simultaneously.
**Answer:** The missing numbers to fill the empty cells to make all rows and columns sum to 24 are:
- Top row right cell: 3
- Middle row left cell: 6
- Middle row right cell: 11
- Bottom row left cell: 5
- Bottom row middle cell: 9
- Bottom row right cell: 10
However, the diagonals do not sum to 24 with these assignments.
**Slug:** magic-square-24
**Subject:** algebra
Magic Square 24 A33103
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