1. **State the problem:** A math class has a total of 41 students. The number of males is 15 more than the number of females. We need to find how many males and females are in the class. 2. **Define variables:** Let $f$ be the number of females and $m$ be the number of males. 3. **Write equations based on the problem:** - Total students: $$m + f = 41$$ - Males are 15 more than females: $$m = f + 15$$ 4. **Substitute the second equation into the first:** $$ (f + 15) + f = 41 $$ 5. **Simplify and solve for $f$:** $$ 2f + 15 = 41 $$ $$ 2f = 41 - 15 $$ $$ 2f = 26 $$ $$ f = \frac{26}{2} = 13 $$ 6. **Find the number of males $m$ using $f$:** $$ m = f + 15 = 13 + 15 = 28 $$ 7. **Answer:** - Number of females: 13 - Number of males: 28 This means there are 13 females and 28 males in the class, which adds up to 41 students total, and the males are exactly 15 more than the females as stated.