1. **State the problem:** A math class has a total of 41 students. The number of males is 15 more than the number of females. We need to find how many males and females are in the class. 2. **Define variables:** Let $f$ be the number of females and $m$ be the number of males. 3. **Write equations based on the problem:** - Total students: $$m + f = 41$$ - Males are 15 more than females: $$m = f + 15$$ 4. **Substitute the second equation into the first:** $$ (f + 15) + f = 41 $$ 5. **Simplify and solve for $f$:** $$ 2f + 15 = 41 $$ $$ 2f = 41 - 15 $$ $$ 2f = 26 $$ $$ f = \frac{26}{2} = 13 $$ 6. **Find the number of males $m$ using $m = f + 15$:** $$ m = 13 + 15 = 28 $$ 7. **Answer:** - Number of females: 13 - Number of males: 28 This means there are 13 females and 28 males in the class.