1. **State the problem:** Simplify the expression $$-3\begin{pmatrix}0 & 6 \\ -5 & 3\end{pmatrix} + \begin{pmatrix}-9 & 8 \\ 5 & 1\end{pmatrix} - 2\begin{pmatrix}4 & 6 \\ -4 & -7\end{pmatrix}$$ 2. **Recall matrix addition and scalar multiplication rules:** - Scalar multiplication: multiply each element of the matrix by the scalar. - Matrix addition: add corresponding elements. 3. **Calculate each scalar multiplication:** $$-3\begin{pmatrix}0 & 6 \\ -5 & 3\end{pmatrix} = \begin{pmatrix}-3 \times 0 & -3 \times 6 \\ -3 \times (-5) & -3 \times 3\end{pmatrix} = \begin{pmatrix}0 & -18 \\ 15 & -9\end{pmatrix}$$ $$-2\begin{pmatrix}4 & 6 \\ -4 & -7\end{pmatrix} = \begin{pmatrix}-2 \times 4 & -2 \times 6 \\ -2 \times (-4) & -2 \times (-7)\end{pmatrix} = \begin{pmatrix}-8 & -12 \\ 8 & 14\end{pmatrix}$$ 4. **Rewrite the expression with these results:** $$\begin{pmatrix}0 & -18 \\ 15 & -9\end{pmatrix} + \begin{pmatrix}-9 & 8 \\ 5 & 1\end{pmatrix} + \begin{pmatrix}-8 & -12 \\ 8 & 14\end{pmatrix}$$ 5. **Add the matrices element-wise:** $$\begin{pmatrix}0 + (-9) + (-8) & -18 + 8 + (-12) \\ 15 + 5 + 8 & -9 + 1 + 14\end{pmatrix} = \begin{pmatrix}-17 & -22 \\ 28 & 6\end{pmatrix}$$ 6. **Final answer:** $$\boxed{\begin{pmatrix}-17 & -22 \\ 28 & 6\end{pmatrix}}$$