1. **State the problem:**
We need to find the maximum cost of each drawer pull if the total bill for a lawnmower and 15 drawer pulls is within a $400 budget.
2. **Given information:**
- Cost of lawnmower = 325
- Number of drawer pulls = 15
- Total budget = 400
3. **Set up the inequality:**
Let $x$ be the cost of each drawer pull.
The total cost is the cost of the lawnmower plus the cost of 15 drawer pulls, which must be less than or equal to 400:
$$325 + 15x \leq 400$$
4. **Solve for $x$:**
Subtract 325 from both sides:
$$\cancel{325} + 15x - \cancel{325} \leq 400 - 325$$
$$15x \leq 75$$
Divide both sides by 15:
$$\frac{15x}{\cancel{15}} \leq \frac{75}{\cancel{15}}$$
$$x \leq 5$$
5. **Interpretation:**
The maximum cost of each drawer pull is 5 to stay within the $400 budget.
**Final answer:**
$$\boxed{5}$$
Max Drawer Cost 3Ac1Ca
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