1. **Problem Statement:** The graph of a business' profit function is given. We need to find the highest possible profit the business can earn. 2. **Understanding the Problem:** The highest possible profit corresponds to the maximum value of the profit function. This is the y-coordinate of the function's maximum point (vertex if quadratic). 3. **Method:** - If the function is quadratic in the form $$y = ax^2 + bx + c$$ with $$a < 0$$, the maximum profit is at the vertex. - The vertex's y-value is given by $$y_{max} = c - \frac{b^2}{4a}$$ or by evaluating the function at $$x = -\frac{b}{2a}$$. 4. **From the graph:** - The highest point on the graph is approximately at profit = 1510 (as indicated by the options and graph scale). 5. **Answer:** The highest possible profit the business can earn is **1510**. This is the maximum value of the profit function as shown on the graph.