1. **State the problem:** We have 7 numbers with a mean of 4. Six of the numbers are 2, 3, 1, 2, 7, and 8. We need to find:
a) The seventh number.
b) The median of all 7 numbers.
2. **Formula for mean:** The mean of $n$ numbers $x_1, x_2, ..., x_n$ is given by
$$\text{mean} = \frac{x_1 + x_2 + ... + x_n}{n}$$
3. **Find the sum of all 7 numbers:** Since the mean is 4 and there are 7 numbers,
$$\text{sum} = \text{mean} \times n = 4 \times 7 = 28$$
4. **Sum of the known six numbers:**
$$2 + 3 + 1 + 2 + 7 + 8 = 23$$
5. **Find the seventh number $x$:**
$$23 + x = 28$$
$$x = 28 - 23 = 5$$
6. **List all 7 numbers including the seventh:**
$$\{1, 2, 2, 3, 5, 7, 8\}$$
7. **Find the median:** The median is the middle number when the numbers are sorted.
Since there are 7 numbers (odd), the median is the 4th number in the sorted list.
The sorted list is already given above.
The 4th number is $3$.
**Final answers:**
- a) The seventh number is $5$.
- b) The median of the numbers is $3$.
Mean Median 338D2D
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