1. The problem states that three number cards have a minimum of 6 and a range of 7.
2. The range is the difference between the maximum and minimum values: $$\text{Range} = \text{Max} - \text{Min}$$
3. Given the minimum is 6 and the range is 7, we find the maximum: $$\text{Max} = 6 + 7 = 13$$
4. We know one card is 6 (minimum), another is 8 (given), and the maximum is 13.
5. The three numbers are 6, 8, and 13.
6. The mean is the average of the numbers: $$\text{Mean} = \frac{6 + 8 + 13}{3} = \frac{27}{3} = 9$$
7. Therefore, the mean of the three numbers is 9.
Mean Range D82B45
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