1. **State the problem:** Two vehicles start at the same time from towns A and B, which are 160 km apart, traveling towards each other. The lorry travels at 45 km/h from A to B, and the car travels at 75 km/h from B to A. We need to find the time they meet and the distance from A to the meeting point C. 2. **Formula and rules:** When two objects move towards each other, the sum of the distances they cover equals the total distance between them. If $t$ is the time in hours after 11:50 am when they meet, then: $$\text{Distance by lorry} + \text{Distance by car} = 160$$ Using speed = distance/time, distances are speed multiplied by time: $$45t + 75t = 160$$ 3. **Solve for $t$:** $$45t + 75t = 160$$ $$120t = 160$$ $$t = \frac{160}{120}$$ $$t = \frac{4}{3} = 1.333... \text{ hours}$$ 4. **Convert time to hours and minutes:** $$1.333... \text{ hours} = 1 \text{ hour } + 0.333... \times 60 \text{ minutes} = 1 \text{ hour } + 20 \text{ minutes}$$ So, they meet 1 hour 20 minutes after 11:50 am, which is at 1:10 pm. 5. **Find distance from A to C:** $$\text{Distance by lorry} = 45 \times \frac{4}{3} = 60 \text{ km}$$ **Final answers:** - Time of meeting: 1:10 pm - Distance from A to C: 60 km