1. **Stating the problem:** Siti has 50 pieces of $5-notes and $2-notes in total. Let $y$ be the number of $5-notes. Then the number of $2-notes is $50 - y$. The total value of all notes is more than 132. 2. **Forming the inequality:** The total value from $5-notes is $5y$ and from $2-notes is $2(50 - y)$. The inequality is: $$5y + 2(50 - y) > 132$$ 3. **Simplifying the inequality:** $$5y + 100 - 2y > 132$$ $$3y + 100 > 132$$ 4. **Isolating $y$:** $$3y > 132 - 100$$ $$3y > 32$$ 5. **Dividing both sides by 3:** $$\cancel{3}y > \cancel{3}\frac{32}{3}$$ $$y > \frac{32}{3}$$ 6. **Interpreting the result:** Since $y$ must be a whole number (number of notes), the minimum number of $5-notes is: $$y = 11$$ **Final answer:** Siti must have at least 11 five-dollar notes.