1. **Stating the problem:** We have a 4x4 grid with shapes in each cell and totals for each row and column. We need to find the missing column total marked with a question mark.
2. **Assign variables to each shape:**
- Let $G$ = value of green triangle
- Let $O$ = value of orange square
- Let $Y$ = value of yellow hexagon
- Let $R$ = value of red circle
3. **Write equations from row totals:**
- Row 1: $G + O + O + G = 28$ which simplifies to $2G + 2O = 28$
- Row 2: $Y + O + Y + O = 30$ which simplifies to $2Y + 2O = 30$
- Row 3: $R + G + R + R = 18$ which simplifies to $3R + G = 18$
- Row 4: $R + O + R + R = 20$ which simplifies to $3R + O = 20$
4. **Simplify row equations:**
- From Row 1: $2G + 2O = 28$ divide both sides by 2:
$$\cancel{2}G + \cancel{2}O = \frac{28}{2}$$
$$G + O = 14$$
- From Row 2: $2Y + 2O = 30$ divide both sides by 2:
$$\cancel{2}Y + \cancel{2}O = \frac{30}{2}$$
$$Y + O = 15$$
5. **Express $G$ from Row 1:**
$$G = 14 - O$$
6. **From Row 3:**
$$3R + G = 18$$ substitute $G$:
$$3R + (14 - O) = 18$$
$$3R = 18 - 14 + O$$
$$3R = 4 + O$$
7. **From Row 4:**
$$3R + O = 20$$
8. **Use equations from steps 6 and 7:**
From step 6: $3R = 4 + O$
From step 7: $3R + O = 20$
Substitute $3R$ from step 6 into step 7:
$$(4 + O) + O = 20$$
$$4 + 2O = 20$$
$$2O = 16$$
$$O = 8$$
9. **Find $G$ and $R$:**
- $G = 14 - O = 14 - 8 = 6$
- From step 6: $3R = 4 + O = 4 + 8 = 12$
$$R = \frac{12}{3} = 4$$
10. **Find $Y$ from step 4:**
$$Y + O = 15$$
$$Y = 15 - O = 15 - 8 = 7$$
11. **Calculate the missing column total (first column):**
Column 1 shapes: Row 1: $G = 6$
Row 2: $Y = 7$
Row 3: $R = 4$
Row 4: $R = 4$
Sum:
$$6 + 7 + 4 + 4 = 21$$
**Final answer:** The missing total is $21$.
Missing Column Total Dac558
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.