1. **State the problem:** We need to find the missing numbers in the equations: $$4 + \_ = 3 + 3$$ $$\_ + 6 = 7 + 2$$ $$8 + \_ = 9 + 1$$ $$\_ + 1 = 3 + 4$$ $$1 + \_ = 4 + 6$$ 2. **Formula and rules:** To find the missing number, use the property of equality: if $a + b = c + d$, then the missing number can be found by isolating it on one side. 3. **Solve each equation step-by-step:** - For $4 + x = 3 + 3$: $$4 + x = 6$$ $$x = 6 - 4$$ $$x = 2$$ - For $x + 6 = 7 + 2$: $$x + 6 = 9$$ $$x = 9 - 6$$ $$x = 3$$ - For $8 + x = 9 + 1$: $$8 + x = 10$$ $$x = 10 - 8$$ $$x = 2$$ - For $x + 1 = 3 + 4$: $$x + 1 = 7$$ $$x = 7 - 1$$ $$x = 6$$ - For $1 + x = 4 + 6$: $$1 + x = 10$$ $$x = 10 - 1$$ $$x = 9$$ 4. **Final answers:** - $4 + 2 = 3 + 3$ - $3 + 6 = 7 + 2$ - $8 + 2 = 9 + 1$ - $6 + 1 = 3 + 4$ - $1 + 9 = 4 + 6$ Each missing number balances the equation, confirming the solution.