Subjects algebra

Missing Point 6C2Feb

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1. The problem asks which ordered pair could be the missing point in the set \{(-4, 3), (5, -1), (0, 2), (x, y)\} so that the relation is a function. 2. A function assigns exactly one output (y-value) for each input (x-value). This means no two ordered pairs can have the same x-value with different y-values. 3. Let's check each option to see if the x-value already exists in the set: - A. (5, 7): x = 5 is already in (5, -1), so adding (5, 7) would give two different y-values for x=5, which is not allowed. - B. (1, -3): x = 1 is not in the set, so this is possible. - C. (0, -6): x = 0 is already in (0, 2), so adding (0, -6) would violate the function rule. - D. (-4, 0): x = -4 is already in (-4, 3), so adding (-4, 0) would violate the function rule. 4. Therefore, the only ordered pair that can be the missing point without violating the function rule is \textbf{(1, -3)}. Final answer: (1, -3)