Subjects algebra

Missing Sequence 261Aea

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1. The problem is to find the missing numbers in the sequence: 73085, ( ), ( ), 73100, ( ). 2. We observe the known numbers 73085 and 73100 with missing numbers in between. 3. Calculate the difference between 73100 and 73085: $$73100 - 73085 = 15$$. 4. There are 4 intervals between the 5 numbers (including missing ones), so each step increases by $$\frac{15}{4} = 3.75$$. 5. Starting from 73085, add 3.75 to find the next numbers: - First missing number: $$73085 + 3.75 = 73088.75$$ - Second missing number: $$73088.75 + 3.75 = 73092.5$$ - Fourth number is given as 73100. - Fifth missing number: $$73100 + 3.75 = 73103.75$$ 6. The complete sequence is: 73085, 73088.75, 73092.5, 73100, 73103.75.