1. The problem is to find the missing numbers in the sequence: 73085, ( ), ( ), 73100, ( ).
2. We observe the known numbers 73085 and 73100 with missing numbers in between.
3. Calculate the difference between 73100 and 73085: $$73100 - 73085 = 15$$.
4. There are 4 intervals between the 5 numbers (including missing ones), so each step increases by $$\frac{15}{4} = 3.75$$.
5. Starting from 73085, add 3.75 to find the next numbers:
- First missing number: $$73085 + 3.75 = 73088.75$$
- Second missing number: $$73088.75 + 3.75 = 73092.5$$
- Fourth number is given as 73100.
- Fifth missing number: $$73100 + 3.75 = 73103.75$$
6. The complete sequence is: 73085, 73088.75, 73092.5, 73100, 73103.75.
Missing Sequence 261Aea
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.