1. **State the problem:** Find the approximate monthly percent change for the function $f(t) = 16(1.4)^t$ which models the number of deer after $t$ years. 2. **Recall the yearly growth factor:** The yearly growth factor is $1.4$ (which corresponds to a 40% increase per year). 3. **Alternative approach using logarithms:** The monthly growth factor $m$ satisfies $m^{12} = 1.4$. 4. **Take natural logarithm on both sides:** $$\ln(m^{12}) = \ln(1.4)$$ $$12 \ln(m) = \ln(1.4)$$ 5. **Solve for $\ln(m)$:** $$\ln(m) = \frac{\ln(1.4)}{12}$$ 6. **Calculate $m$:** $$m = e^{\frac{\ln(1.4)}{12}}$$ 7. **Calculate approximate value:** $$\ln(1.4) \approx 0.33647$$ $$m = e^{0.33647/12} = e^{0.02804} \approx 1.0284$$ 8. **Find monthly percent change:** $$\text{percent change} = (m - 1) \times 100 = (1.0284 - 1) \times 100 = 2.84\%$$ **Final answer:** The approximate monthly percent change is **2.84%**.