1. **State the problem:** Multiply the mixed numbers $-3 \frac{1}{4}$ and $-2 \frac{3}{5}$. 2. **Convert mixed numbers to improper fractions:** $$-3 \frac{1}{4} = -\left(3 + \frac{1}{4}\right) = -\frac{13}{4}$$ $$-2 \frac{3}{5} = -\left(2 + \frac{3}{5}\right) = -\frac{13}{5}$$ 3. **Multiply the improper fractions:** $$\left(-\frac{13}{4}\right) \times \left(-\frac{13}{5}\right) = \frac{(-13) \times (-13)}{4 \times 5} = \frac{169}{20}$$ 4. **Simplify the fraction if possible:** $\frac{169}{20}$ cannot be simplified further because 169 is $13^2$ and 20 factors as $2^2 \times 5$. 5. **Convert the improper fraction back to a mixed number:** Divide 169 by 20: $$169 \div 20 = 8 \text{ remainder } 9$$ So, $$\frac{169}{20} = 8 \frac{9}{20}$$ 6. **Determine the sign:** Multiplying two negative numbers results in a positive number, so the answer is positive. **Final answer:** $$8 \frac{9}{20}$$ This corresponds to choice **D. 8 9/20**.