1. **State the problem:** Multiply the expressions $6pq^2$ and $2qr^2$.
2. **Recall the multiplication rule for algebraic expressions:** Multiply the coefficients (numbers) and then multiply the variables by adding their exponents if they have the same base.
3. **Multiply the coefficients:**
$$6 \times 2 = 12$$
4. **Multiply the variables:**
- For $p$, it appears only in the first term, so it remains $p$.
- For $q$, we have $q^2$ and $q^1$ (since $q$ is the same as $q^1$), so add exponents: $2 + 1 = 3$, giving $q^3$.
- For $r$, it appears only in the second term as $r^2$.
5. **Combine all parts:**
$$12 p q^3 r^2$$
6. **Final answer:**
$$12 p q^3 r^2$$
Multiply Polynomials 140Daa
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