1. Problem: Multiply \( \frac{12x^3}{25} \times \frac{40}{9x^2} \). 2. Formula: Multiply numerators and denominators separately: \( \frac{a}{b} \times \frac{c}{d} = \frac{ac}{bd} \). 3. Work: - Numerator: \(12x^3 \times 40 = 480x^3\) - Denominator: \(25 \times 9x^2 = 225x^2\) - Expression: \( \frac{480x^3}{225x^2} \) 4. Simplify: - Cancel \(x^2\) from numerator and denominator: \( \frac{480x^{3-2}}{225} = \frac{480x}{225} \) - Simplify fraction \( \frac{480}{225} = \frac{32}{15} \) (dividing numerator and denominator by 15) 5. Final answer: \[ \frac{32x}{15} \] 6. Restriction: \(x \neq 0\) (to avoid division by zero in original expression). Your work is correct except the restriction should be \(x \neq 0\), not \(x \neq 2\).