1. The problem asks to find the product of $\sqrt{b} \cdot \sqrt{b}$ assuming $b \geq 0$. 2. Recall the property of square roots: $\sqrt{x} \cdot \sqrt{y} = \sqrt{xy}$ for $x,y \geq 0$. 3. Applying this property, we get: $$\sqrt{b} \cdot \sqrt{b} = \sqrt{b \cdot b}$$ 4. Simplify inside the square root: $$\sqrt{b^2}$$ 5. Since $b \geq 0$, the square root of $b^2$ is $b$: $$\sqrt{b^2} = b$$ 6. Therefore, the product $\sqrt{b} \cdot \sqrt{b} = b$. Final answer: $b$