1. We are asked to simplify the expression $$\left(-\frac{1}{4}\right)^{-3}$$. 2. Recall the rule for negative exponents: $$a^{-n} = \frac{1}{a^n}$$ where $a \neq 0$. 3. Applying this rule, we rewrite the expression as: $$\left(-\frac{1}{4}\right)^{-3} = \frac{1}{\left(-\frac{1}{4}\right)^3}$$ 4. Next, calculate the cube of $$-\frac{1}{4}$$: $$\left(-\frac{1}{4}\right)^3 = \left(-1\right)^3 \times \left(\frac{1}{4}\right)^3 = -1 \times \frac{1}{64} = -\frac{1}{64}$$ 5. Substitute back: $$\frac{1}{\left(-\frac{1}{4}\right)^3} = \frac{1}{-\frac{1}{64}}$$ 6. Dividing by a fraction is the same as multiplying by its reciprocal: $$\frac{1}{-\frac{1}{64}} = 1 \times \left(-64\right) = -64$$ 7. Therefore, the simplified value of $$\left(-\frac{1}{4}\right)^{-3}$$ is $$\boxed{-64}$$.