1. Let's clarify the problem: You are asking why the solution in problem number 8 does not have negative signs on the left-hand side (LHS) of the equation. 2. Generally, when solving equations, the presence or absence of negative signs depends on the original equation and the algebraic manipulations performed. 3. Important rule: When you multiply or divide both sides of an equation by a negative number, the inequality sign reverses (if it's an inequality), but for equations, the equality remains, and signs may change accordingly. 4. Another key point: Sometimes, negative signs can be factored out or canceled if they appear on both sides or within terms. 5. Without the exact equation from problem 8, a common reason for no negative signs on the LHS is that the equation was multiplied or divided by -1 to simplify it, or the negative terms were moved to the right-hand side. 6. For example, if the original equation was $$-x = 5$$, multiplying both sides by $$-1$$ gives $$x = -5$$, removing the negative sign from the LHS. 7. Therefore, the absence of negative signs on the LHS in problem 8 likely results from algebraic simplification steps that maintain equality but rearrange signs for clarity. If you provide the exact equation from problem 8, I can give a more precise explanation.