1. The problem asks to find a second equation so that the system with the first equation has no solutions. 2. The first equation is given as $$y=\frac{3}{4}x - 3$$. 3. For a system of two linear equations to have no solutions, the lines must be parallel but not the same line. 4. Parallel lines have the same slope but different y-intercepts. 5. The slope of the first line is $$\frac{3}{4}$$. 6. Therefore, the second equation must have slope $$\frac{3}{4}$$ but a different y-intercept. 7. An example of such a second equation is $$y=\frac{3}{4}x + 1$$. 8. This ensures the lines are parallel and will never intersect, so the system has no solutions. Final answer: $$y=\frac{3}{4}x + 1$$