1. **Problem statement:** Find the zeros (Nullstellen) of the function given in factor form: $$f(x) = x(x-2)(x+3)$$ 2. **Formula and rules:** The zeros of a function in factor form are the values of $x$ that make any factor equal to zero. For a product of factors, the zero occurs when any single factor is zero. 3. **Step-by-step solution:** - Set each factor equal to zero: $$x = 0$$ $$(x-2) = 0$$ $$(x+3) = 0$$ - Solve each equation: $$x = 0$$ $$x = 2$$ $$x = -3$$ 4. **Explanation:** Since the function is a product of three factors, the function equals zero whenever any one of these factors is zero. Thus, the zeros of $f(x)$ are $0$, $2$, and $-3$. **Final answer:** The zeros of $f(x)$ are $$\boxed{0, 2, -3}$$