1. **State the problem:** Three times a number decreased by 5 equals 16.
2. **Translate the problem into an equation:** Let the number be $x$. Then, three times the number is $3x$. Decreased by 5 means subtracting 5, so the equation is:
$$3x - 5 = 16$$
3. **Solve the equation:**
Add 5 to both sides to isolate the term with $x$:
$$3x - 5 + 5 = 16 + 5$$
$$3x = 21$$
4. **Divide both sides by 3 to solve for $x$:**
$$\frac{\cancel{3}x}{\cancel{3}} = \frac{21}{3}$$
$$x = 7$$
5. **Answer:** The number is $7$.
This means if you take 3 times 7, which is 21, and then subtract 5, you get 16, confirming the solution.
Number Equation B551E4
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.