1. **State the problem:** Jason spent $\frac{3}{7}$ of his money on 24 apples and 37 oranges. The cost of one orange is three times the cost of one apple. Then he spent $\frac{1}{5}$ of his remaining money to buy more oranges. We need to find the total number of oranges Jason bought. 2. **Define variables:** Let the cost of one apple be $a$. Then the cost of one orange is $3a$. 3. **Calculate total cost of first purchase:** $$\text{Cost of apples} = 24a$$ $$\text{Cost of oranges} = 37 \times 3a = 111a$$ $$\text{Total cost} = 24a + 111a = 135a$$ 4. **Relate total cost to money spent:** Jason spent $\frac{3}{7}$ of his money on this, so if total money is $M$: $$135a = \frac{3}{7}M$$ 5. **Express $a$ in terms of $M$:** $$a = \frac{3M}{7 \times 135} = \frac{M}{315}$$ 6. **Calculate remaining money after first purchase:** $$M - \frac{3}{7}M = \frac{4}{7}M$$ 7. **Money spent on second purchase:** He spent $\frac{1}{5}$ of remaining money: $$\frac{1}{5} \times \frac{4}{7}M = \frac{4}{35}M$$ 8. **Cost of one orange:** $$3a = 3 \times \frac{M}{315} = \frac{M}{105}$$ 9. **Number of oranges bought in second purchase:** $$\text{Number} = \frac{\text{Money spent}}{\text{Cost per orange}} = \frac{\frac{4}{35}M}{\frac{M}{105}} = \frac{4}{35}M \times \frac{105}{M} = 12$$ 10. **Total oranges bought:** $$37 + 12 = 49$$ **Final answer:** Jason bought **49** oranges altogether.