1. **State the problem:** We need to order the numbers $2 \frac{7}{10}$, $\frac{7}{2}$, $3.1$, $\frac{49}{5}$, $\frac{29}{4}$, and $3 \frac{9}{20}$ from smallest to biggest. 2. **Convert all numbers to decimals for easy comparison:** - $2 \frac{7}{10} = 2 + \frac{7}{10} = 2 + 0.7 = 2.7$ - $\frac{7}{2} = 3.5$ - $3.1$ is already a decimal. - $\frac{49}{5} = 9.8$ - $\frac{29}{4} = 7.25$ - $3 \frac{9}{20} = 3 + \frac{9}{20} = 3 + 0.45 = 3.45$ 3. **List the decimal equivalents:** $2.7, 3.5, 3.1, 9.8, 7.25, 3.45$ 4. **Order the decimals from smallest to biggest:** $2.7 < 3.1 < 3.45 < 3.5 < 7.25 < 9.8$ 5. **Match back to original numbers:** $2 \frac{7}{10} < 3.1 < 3 \frac{9}{20} < \frac{7}{2} < \frac{29}{4} < \frac{49}{5}$ **Final answer:** $$2 \frac{7}{10}, 3.1, 3 \frac{9}{20}, \frac{7}{2}, \frac{29}{4}, \frac{49}{5}$$