1. **State the problem:** Verify the order of the rational numbers $\frac{4}{11}$, $\frac{6}{17}$, $\frac{2}{5}$, $\frac{3}{7}$, $\frac{5}{12}$, and $\frac{3}{8}$ from least to greatest. 2. **Method:** We will compare fractions by cross-multiplying to avoid decimal approximation errors. 3. **Compare pairs step-by-step:** - Compare $\frac{6}{17}$ and $\frac{4}{11}$: cross multiply $6 \times 11 = 66$ and $4 \times 17 = 68$, since $66 < 68$, $\frac{6}{17} < \frac{4}{11}$. - Compare $\frac{4}{11}$ and $\frac{3}{8}$: $4 \times 8 = 32$ and $3 \times 11 = 33$, since $32 < 33$, $\frac{4}{11} < \frac{3}{8}$. - Compare $\frac{3}{8}$ and $\frac{2}{5}$: $3 \times 5 = 15$ and $2 \times 8 = 16$, since $15 < 16$, $\frac{3}{8} < \frac{2}{5}$. - Compare $\frac{2}{5}$ and $\frac{5}{12}$: $2 \times 12 = 24$ and $5 \times 5 = 25$, since $24 < 25$, $\frac{2}{5} < \frac{5}{12}$. - Compare $\frac{5}{12}$ and $\frac{3}{7}$: $5 \times 7 = 35$ and $3 \times 12 = 36$, since $35 < 36$, $\frac{5}{12} < \frac{3}{7}$. 4. **Conclusion:** The order from least to greatest is: $$\frac{6}{17} < \frac{4}{11} < \frac{3}{8} < \frac{2}{5} < \frac{5}{12} < \frac{3}{7}$$ This confirms the previous answer is correct.