1. **State the problem:** Renna and her packages have a total mass of 620 kg, which exceeds the elevator's mass limit of 450 kg. Each package has a mass of 37.4 kg. We want to find the minimum number of packages, $p$, Renna must remove so that the total mass is at most 450 kg. 2. **Write the inequality:** Let $p$ be the number of packages removed. The total mass after removing $p$ packages is $$620 - 37.4p.$$ This must be less than or equal to the mass limit 450 kg, so the inequality is: $$620 - 37.4p \leq 450$$ 3. **Solve the inequality:** Subtract 450 from both sides: $$620 - 37.4p - 450 \leq 0$$ Simplify: $$170 - 37.4p \leq 0$$ Subtract 170 from both sides: $$-37.4p \leq -170$$ Divide both sides by -37.4, remembering to reverse the inequality sign because we are dividing by a negative number: $$p \geq \frac{170}{37.4}$$ Calculate the right side: $$p \geq 4.548$$ 4. **Interpret the result:** Since $p$ must be a whole number of packages, Renna must remove at least 5 packages to meet the mass requirement. **Final answer:** - Inequality: $$620 - 37.4p \leq 450$$ - Minimum packages to remove: $$5$$