1. The problem asks whether the graph of the equation $y^2 = 8x$ represents a function. 2. Recall the definition of a function: for every input $x$, there must be exactly one output $y$. 3. The equation $y^2 = 8x$ can be rewritten as $y = \pm \sqrt{8x}$, which means for some values of $x$, there are two possible $y$ values (one positive and one negative). 4. This implies that a vertical line (e.g., $x=3$) will intersect the graph at two points: $(3, \sqrt{24})$ and $(3, -\sqrt{24})$. 5. Since there exists at least one vertical line intersecting the graph at more than one point, the graph does not pass the vertical line test. 6. Therefore, the graph is not a function. Final answer: B. No, the graph is not a function because a vertical line $x=3$ intersects the graph at two points.