1. **State the problem:** We are given a parabola opening upward with vertex at about $(0, -2)$ and x-intercepts at about $(-2, 0)$ and $(2, 0)$. We need to find the minimum value of the graph. 2. **Recall the properties of a parabola:** For a parabola in the form $y = ax^2 + bx + c$ with $a > 0$, the graph opens upward and the vertex represents the minimum point. 3. **Identify the vertex:** The vertex is given as $(0, -2)$, which means the minimum value of the parabola is the $y$-coordinate of the vertex. 4. **Conclusion:** The minimum value of the graph is $$-2$$ because the vertex is the lowest point on the parabola. Therefore, the minimum value of the graph is **-2**.