1. The problem asks to determine the vertex of a parabola given its graph. 2. The vertex of a parabola in the form $y = ax^2 + bx + c$ is given by the formula for the x-coordinate: $$x = -\frac{b}{2a}$$ and the y-coordinate is found by substituting this x back into the equation. 3. However, since the graph is given and the vertex is visually identified at approximately $(0, 3)$, we can directly state the vertex coordinates. 4. The vertex is the point where the parabola changes direction, and since the parabola opens upward, this point is a minimum. 5. From the graph description, the vertex is at $x=0$ and $y=3$. 6. Therefore, the vertex of the parabola is $$\boxed{(0, 3)}$$.