1. The problem asks to identify the vertex, focus, directrix, and axis of symmetry for the parabola given by the equation $$y = -3$$ and related information. 2. Since $$y = -3$$ is a horizontal line, it is likely the directrix of a parabola. The parabola opens either upward or downward with vertex and focus aligned vertically. 3. The vertex lies halfway between the focus and directrix. If the directrix is $$y = -3$$ and the parabola opens upward, the vertex is above this line. 4. For a parabola with vertical axis of symmetry, the standard form is $$ (x - h)^2 = 4p(y - k) $$ where $$(h,k)$$ is the vertex and $$p$$ is the distance from vertex to focus (positive if opening upward, negative if downward). 5. Given the directrix $$y = -3$$, if the vertex is at the origin $$(0,0)$$, then the distance $$p$$ is the distance from vertex to directrix: $$p = 3$$. 6. The focus is then at $$ (0, p) = (0, 3) $$. 7. The equation of the parabola is $$ (x - 0)^2 = 4(3)(y - 0) $$ or $$ x^2 = 12y $$. 8. The axis of symmetry is the vertical line $$x = 0$$. Final answer: - Vertex: $$(0,0)$$ - Focus: $$(0,3)$$ - Directrix: $$y = -3$$ - Axis of symmetry: $$x = 0$$