1. We are given a line $k$ with equation $y = -1.4x + 5$ and a point $A(0, 3.4)$ through which line $N$ passes. 2. Since line $N$ is parallel to line $k$, it has the same slope. The slope of $k$ is $-1.4$. 3. The general formula for a line is $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept. 4. For line $N$, we know $m = -1.4$ and it passes through $A(0, 3.4)$, so when $x=0$, $y=3.4$. 5. Substitute $x=0$ and $y=3.4$ into $y = -1.4x + b$ to find $b$: $$3.4 = -1.4 \times 0 + b$$ $$3.4 = b$$ 6. Therefore, the equation of line $N$ is: $$y = -1.4x + 3.4$$