1. **State the problem:** We need to find the equation of a line parallel to line A that passes through point P. 2. **Identify the slope of line A:** Line A passes through points (0, -2) and (4, 2). 3. **Calculate the slope $m$ of line A:** $$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{2 - (-2)}{4 - 0} = \frac{4}{4} = 1$$ 4. **Since parallel lines have the same slope, the new line also has slope $m = 1$.** 5. **Use the point-slope form of a line equation:** $$y = mx + c$$ 6. **Substitute the slope $m = 1$ and point P $(0, 3)$ into the equation to find $c$:** $$3 = 1 \times 0 + c \Rightarrow c = 3$$ 7. **Write the equation of the line:** $$y = 1x + 3$$ 8. **Simplify:** $$y = x + 3$$ **Final answer:** The equation of the line parallel to line A passing through point P is $$y = x + 3$$