1. **State the problem:** Find the equation of the line parallel to $y=3x-2$ that passes through the point $(2,11)$. 2. **Recall the rule for parallel lines:** Parallel lines have the same slope. The slope of the given line is $3$. 3. **Use the point-slope form:** The equation of a line with slope $m$ passing through $(x_1,y_1)$ is $$y - y_1 = m(x - x_1)$$ Substitute $m=3$, $x_1=2$, and $y_1=11$: $$y - 11 = 3(x - 2)$$ 4. **Simplify the equation:** $$y - 11 = 3x - 6$$ Add $11$ to both sides: $$y = 3x - 6 + 11$$ $$y = 3x + 5$$ 5. **Final answer:** The equation of the line parallel to $y=3x-2$ passing through $(2,11)$ is $$y = 3x + 5$$