Subjects algebra

Parallel Line C508Dd

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1. **State the problem:** Find the equation of a line passing through the point $(2,8)$ and parallel to the line segment $GH$. 2. **Identify the slope of line $GH$:** The line $GH$ is decreasing, so its slope is negative. To find the exact slope, we need coordinates of points $G$ and $H$. Since the graph is described but no exact coordinates are given, let's assume $G=(x_1,y_1)$ and $H=(x_2,y_2)$ with $x_1 < x_2$ and $y_1 > y_2$. 3. **Calculate slope $m$ of $GH$:** $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ 4. **Equation of line parallel to $GH$:** Parallel lines have the same slope. So the new line passing through $(2,8)$ has slope $m$. 5. **Use point-slope form:** $$y - y_1 = m(x - x_1)$$ Substitute $(x_1,y_1) = (2,8)$: $$y - 8 = m(x - 2)$$ 6. **Final equation:** $$y = m(x - 2) + 8$$ Since exact coordinates of $G$ and $H$ are not provided, the equation is expressed in terms of $m$. If you provide coordinates of $G$ and $H$, I can calculate the exact equation.