1. **Problem:** Write an equation in slope-intercept form of the line that passes through the point (1, 3) and is parallel to the graph of the equation $y = 3x + 2$. 2. **Recall:** The slope-intercept form of a line is given by: $$y = mx + b$$ where $m$ is the slope and $b$ is the y-intercept. 3. **Important rule:** Lines that are parallel have the same slope. 4. From the given equation $y = 3x + 2$, the slope $m = 3$. 5. Since the new line is parallel, its slope is also $3$. 6. Use the point-slope form to find the equation of the new line passing through $(1, 3)$: $$y - y_1 = m(x - x_1)$$ where $(x_1, y_1) = (1, 3)$ and $m = 3$. 7. Substitute values: $$y - 3 = 3(x - 1)$$ 8. Simplify: $$y - 3 = 3x - 3$$ 9. Add 3 to both sides: $$y = 3x - 3 + 3$$ 10. Simplify: $$y = 3x$$ **Final answer:** $$y = 3x$$