1. **State the problem:** We have the old route equation $$y = \frac{2}{5}x - 4$$ and want the equation of a new route parallel to it passing through point $ (Q, P) $. 2. **Recall the rule for parallel lines:** Parallel lines have the same slope. The slope of the old route is $$m = \frac{2}{5}$$. So the new route must have slope $$\frac{2}{5}$$. 3. **Use point-slope form:** The equation of a line with slope $m$ passing through point $(x_1,y_1)$ is $$y - y_1 = m(x - x_1)$$. 4. **Apply to our problem:** Substitute $m = \frac{2}{5}$, $x_1 = Q$, and $y_1 = P$: $$y - P = \frac{2}{5}(x - Q)$$ 5. **Check the options:** The correct equation is $$y - P = \frac{2}{5}(x - Q)$$. **Final answer:** $$y - P = \frac{2}{5}(x - Q)$$