1. The problem involves two linear equations: $$y = -10x - 1$$ and $$y = -10x - \frac{8}{3}$$. 2. Both lines have the same slope, $$m = -10$$, but different y-intercepts, $$b_1 = -1$$ and $$b_2 = -\frac{8}{3}$$. 3. The formula for a line is $$y = mx + b$$, where $$m$$ is the slope and $$b$$ is the y-intercept. 4. Since the slopes are equal and the y-intercepts are different, these lines are parallel and will never intersect. 5. Graphically, both lines are straight and decline steeply because the slope is negative. 6. The first line crosses the y-axis at $$-1$$, and the second crosses at $$-\frac{8}{3}$$, which is approximately $$-2.67$$. 7. Therefore, the two lines are parallel with no points of intersection.