1. **State the problem:** We are given the area of a parallelogram as $28x^2 + 37x + 12$ square meters and its base as $4x + 3$ meters. We need to find the height.
2. **Formula:** The area $A$ of a parallelogram is given by:
$$A = \text{base} \times \text{height}$$
3. **Apply the formula:** Let the height be $h$. Then:
$$28x^2 + 37x + 12 = (4x + 3) \times h$$
4. **Solve for height $h$:**
$$h = \frac{28x^2 + 37x + 12}{4x + 3}$$
5. **Simplify the expression:** We perform polynomial division or factor numerator and denominator.
Factor numerator:
$$28x^2 + 37x + 12 = (4x + 3)(7x + 4)$$
6. **Substitute back:**
$$h = \frac{(4x + 3)(7x + 4)}{4x + 3}$$
7. **Cancel common factor:**
$$h = \cancel{\frac{(4x + 3)(7x + 4)}{4x + 3}} = 7x + 4$$
8. **Final answer:**
The height of the parallelogram is:
$$\boxed{7x + 4}$$
Parallelogram Height 9C8F09
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