1. The problem gives parametric equations: $$y = t^6 - 5$$ and $$x = 4^3 - 1$$. 2. First, simplify the expression for $$x$$ since it does not depend on $$t$$: $$4^3 = 64$$, so $$x = 64 - 1 = 63$$. 3. This means $$x$$ is constant at 63 for all values of $$t$$. 4. The equation for $$y$$ depends on $$t$$ and is $$y = t^6 - 5$$. 5. Since $$x$$ is constant, the parametric curve is a vertical line at $$x = 63$$ with $$y$$ values changing according to $$t^6 - 5$$. 6. The final parametric form is: $$x = 63$$ $$y = t^6 - 5$$ This describes a vertical line where $$y$$ varies with $$t$$.