1. **Problem Statement:** Find the value of $k$ in each term of the expansion of $$\left(2x-\frac{1}{3}y\right)^{10}$$ corresponding to the given terms.
2. **Formula:** The general term in the binomial expansion of $$(a+b)^n$$ is given by
$$T_{r+1} = \binom{n}{r} a^{n-r} b^r$$
where $r=0,1,2,\ldots,n$.
3. **Apply to our problem:** Here, $a=2x$, $b=-\frac{1}{3}y$, and $n=10$. So,
$$T_{r+1} = \binom{10}{r} (2x)^{10-r} \left(-\frac{1}{3}y\right)^r = \binom{10}{r} 2^{10-r} (-1)^r \frac{1}{3^r} x^{10-r} y^r$$
4. **Match terms:** Each term is of the form
$$k x^{10-r} y^r$$
where
$$k = \binom{10}{r} 2^{10-r} (-1)^r \frac{1}{3^r}$$
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**a) Term: $k x^8 y^2$**
- Here, $x$ exponent is 8, so $10-r=8 \Rightarrow r=2$.
- Calculate $k$:
$$k = \binom{10}{2} 2^{8} (-1)^2 \frac{1}{3^2} = 45 \times 256 \times 1 \times \frac{1}{9} = \frac{45 \times 256}{9}$$
- Simplify:
$$\frac{45}{9} = 5 \Rightarrow k = 5 \times 256 = 1280$$
**Answer:** $k=1280$
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**b) Term: $k x^5 y^5$**
- $10-r=5 \Rightarrow r=5$
- Calculate $k$:
$$k = \binom{10}{5} 2^{5} (-1)^5 \frac{1}{3^5} = 252 \times 32 \times (-1) \times \frac{1}{243} = -\frac{252 \times 32}{243}$$
- Simplify numerator:
$$252 \times 32 = 8064$$
- So,
$$k = -\frac{8064}{243}$$
**Answer:** $k = -\frac{8064}{243}$
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**c) Term: $-\frac{5120}{9} x^k y^3$**
- $r=3$ (since power of $y$ is 3)
- The coefficient from formula:
$$k_{coef} = \binom{10}{3} 2^{10-3} (-1)^3 \frac{1}{3^3} = 120 \times 2^{7} \times (-1) \times \frac{1}{27}$$
- Calculate:
$$2^{7} = 128$$
$$k_{coef} = 120 \times 128 \times (-1) \times \frac{1}{27} = -\frac{15360}{27} = -\frac{5120}{9}$$
- This matches the given coefficient exactly.
- The power of $x$ is $10-r = 10-3=7$.
**Answer:** $k=7$
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**d) Term: $\frac{20}{729} x^2 y^{k+3}$**
- Power of $x$ is 2, so $10-r=2 \Rightarrow r=8$
- Power of $y$ is $k+3$, but from formula power of $y$ is $r=8$, so
$$k+3=8 \Rightarrow k=5$$
- Check coefficient:
$$k_{coef} = \binom{10}{8} 2^{2} (-1)^8 \frac{1}{3^8} = 45 \times 4 \times 1 \times \frac{1}{6561} = \frac{180}{6561} = \frac{20}{729}$$
- Matches given coefficient.
**Answer:** $k=5$
Pascal Expansion 2Dc31A
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