1. **State the problem:** We need to find the percent change in the number of people who went to the pool between the first and last weeks. 2. **Identify the weekly attendance:** - Week 1: 1060 people - Week 2: 105 fewer than Week 1, so $$1060 - 105 = 955$$ people - Week 3: 135 more than Week 2, so $$955 + 135 = 1090$$ people - Week 4: 136 fewer than Week 3, so $$1090 - 136 = 954$$ people 3. **Formula for percent change:** $$\text{Percent Change} = \frac{\text{New Value} - \text{Original Value}}{\text{Original Value}} \times 100$$ 4. **Apply the formula:** $$\text{Percent Change} = \frac{954 - 1060}{1060} \times 100 = \frac{-106}{1060} \times 100 = -10\%$$ 5. **Interpretation:** The negative sign indicates a decrease. So, there was a 10% decrease in the number of people who went to the pool from the first to the last week. --- 6. **Second problem:** Find the greatest percent error for a prediction of the winning time 22.3 seconds to the nearest tenth of a percent. 7. **Understanding percent error:** $$\text{Percent Error} = \frac{|\text{Predicted} - \text{Actual}|}{\text{Actual}} \times 100$$ 8. **Since predictions are to the nearest tenth, the maximum error in prediction is 0.05 seconds.** 9. **Calculate greatest percent error:** $$\frac{0.05}{22.3} \times 100 \approx 0.2242\%$$ 10. **Rounded to the nearest tenth of a percent:** 0.2% is the greatest percent error. --- **Final answers:** - Percent change in pool attendance: 10% decrease - Greatest percent error in sprint time prediction: 0.2%