1. Stating the problem: A is greater than B by 10%, and B is greater than C by 20%. Given C = 20, find A.
2. Important formulas and rules:
- If A is greater than B by p%, then $A = B \times (1 + \frac{p}{100})$.
- We will use this formula twice: first to find B from C, then A from B.
3. Find B from C:
Since B is greater than C by 20%,
$$B = C \times (1 + \frac{20}{100}) = 20 \times 1.20 = 24$$
4. Find A from B:
Since A is greater than B by 10%,
$$A = B \times (1 + \frac{10}{100}) = 24 \times 1.10 = 26.4$$
5. Final answer:
$$\boxed{A = 26.4}$$
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