Subjects algebra

Percentage Problems Cebe1C

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1. The problem involves calculating the missing value in a percentage proportion setup where two known values and a percentage are given, or vice versa. 2. The general formula for percentage problems is: $$\text{Part} = \frac{\text{Percentage}}{100} \times \text{Whole}$$ 3. We can rearrange this formula to find any missing value: - To find the Part: $$\text{Part} = \frac{\text{Percentage}}{100} \times \text{Whole}$$ - To find the Whole: $$\text{Whole} = \frac{\text{Part} \times 100}{\text{Percentage}}$$ - To find the Percentage: $$\text{Percentage} = \frac{\text{Part}}{\text{Whole}} \times 100$$ 4. Let's solve each problem step-by-step: **2.** Given 34%, 2, and 0.68 Calculate if 0.68 is the part of 2 at 34%: $$\frac{34}{100} \times 2 = 0.68$$ So, 0.68 is correct. **3.** Given 35%, 140, and 400 Calculate the part: $$\frac{35}{100} \times 400 = 140$$ So, 140 is correct. **5.** Given 70%, 10, and 7 Calculate the part: $$\frac{70}{100} \times 10 = 7$$ So, 7 is correct. **6.** Given 60%, 21, and 35 Calculate the part: $$\frac{60}{100} \times 35 = 21$$ So, 21 is correct. **8.** Given 150 and 15, find the percentage: $$\text{Percentage} = \frac{15}{150} \times 100 = 10\%$$ **9.** Given 15%, 250, and 37.5 Calculate the part: $$\frac{15}{100} \times 250 = 37.5$$ So, 37.5 is correct. **11.** Given 180%, 350, find the part: $$\frac{180}{100} \times 350 = 630$$ **12.** Given 4% and 23.6, find the part: $$\frac{4}{100} \times 23.6 = 0.944$$ **14.** Given 92, 46, and 18 Calculate the percentage: $$\text{Percentage} = \frac{18}{46} \times 100 \approx 39.13\%$$ **15.** Given 10% and 4.5, find the part: $$\frac{10}{100} \times 4.5 = 0.45$$ 5. Summary: Each problem uses the percentage formula to find the missing value by substituting the known values and solving accordingly.