1. **Problem 4a:** What percent of 200 is 11?
The formula for percentage is:
$$\text{Percentage} = \frac{\text{Part}}{\text{Base}} \times 100$$
Here, Part = 11, Base = 200.
Calculate:
$$\frac{11}{200} \times 100 = 5.5\%$$
2. **Problem 4b:** 0.1 is 20% of what number?
Let the number be $x$. Then:
$$0.1 = 20\% \times x = \frac{20}{100} \times x = 0.2x$$
Solve for $x$:
$$x = \frac{0.1}{0.2}$$
Show cancellation:
$$x = \frac{0.1}{\cancel{0.2}} \times \frac{\cancel{1}}{1} = 0.5$$
3. **Problem 4c:** Find 250% of 250.
$$250\% = \frac{250}{100} = 2.5$$
Calculate:
$$2.5 \times 250 = 625$$
4. **Problem 4d:** 20% of what number is 7?
Let the number be $y$.
$$20\% \times y = 7$$
$$\frac{20}{100} y = 7$$
Solve for $y$:
$$y = \frac{7}{\frac{20}{100}} = \frac{7}{0.2}$$
Show cancellation:
$$y = \frac{7}{\cancel{0.2}} \times \frac{\cancel{1}}{1} = 35$$
5. **Problem 5:** Justin earned 63 out of 75 points, Stephanie earned 63 out of 70. Find difference in percent scores.
Justin's percentage:
$$\frac{63}{75} \times 100 = 84\%$$
Stephanie's percentage:
$$\frac{63}{70} \times 100 = 90\%$$
Difference:
$$90\% - 84\% = 6\%$$
6. **Problem 6:** Fire department received 71 false alarms out of 639. What percent were not false?
Number not false:
$$639 - 71 = 568$$
Percent not false:
$$\frac{568}{639} \times 100 \approx 88.89\%$$
7. **Problem 7:** Six middle schools sent bands, which is 30% of all middle schools. Find total number.
Let total schools be $N$.
$$30\% \times N = 6$$
$$\frac{30}{100} N = 6$$
Solve for $N$:
$$N = \frac{6}{0.3} = 20$$
8. **Problem 8a:** 29% + 25% = 54% prefer pepperoni or cheese. If 590 students prefer these, total surveyed is:
Let total be $T$.
$$54\% \times T = 590$$
$$0.54 T = 590$$
$$T = \frac{590}{0.54} \approx 1092.59 \approx 1093$$
8b. If 2000 students surveyed, how many answered "Other" (6%)?
$$6\% \times 2000 = 0.06 \times 2000 = 120$$
9. **Problem 9:** Joyce's age is 25% of Marta's, Marta's is 50% of Cesar's. Joyce is 11.
Let Cesar's age be $C$.
Marta's age:
$$M = 0.5 C$$
Joyce's age:
$$J = 0.25 M = 11$$
Substitute $M$:
$$0.25 \times 0.5 C = 11$$
$$0.125 C = 11$$
Solve for $C$:
$$C = \frac{11}{0.125} = 88$$
Find $M$:
$$M = 0.5 \times 88 = 44$$
**Final answers:**
4a: 5.5%
4b: 0.5
4c: 625
4d: 35
5: 6%
6: 88.89%
7: 20
8a: 1093
8b: 120
9: Marta 44, Cesar 88
Percentage Problems E769D2
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