1. **State the problem:** Find the equation of the line passing through the point $(2, -1)$ and perpendicular to the line given by $2x - y = 4$.
2. **Rewrite the given line in slope-intercept form:**
$$2x - y = 4 \implies -y = 4 - 2x \implies y = 2x - 4$$
The slope of this line is $m = 2$.
3. **Find the slope of the perpendicular line:**
The slope of a line perpendicular to another with slope $m$ is the negative reciprocal:
$$m_{\perp} = -\frac{1}{m} = -\frac{1}{2}$$
4. **Use point-slope form to find the equation of the perpendicular line:**
The point-slope form is:
$$y - y_1 = m(x - x_1)$$
Substitute $m = -\frac{1}{2}$ and point $(2, -1)$:
$$y - (-1) = -\frac{1}{2}(x - 2)$$
$$y + 1 = -\frac{1}{2}x + 1$$
5. **Simplify the equation:**
$$y = -\frac{1}{2}x + 1 - 1$$
$$y = -\frac{1}{2}x$$
**Final answer:**
$$y = -\frac{1}{2}x$$
Perpendicular Line 23128C
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