1. **State the problem:** We need to find the equation of a line passing through point $P(0,0)$ that is perpendicular to the line given by $$y = -9x - 1.$$\n\n2. **Recall the slope of the given line:** The line is in slope-intercept form $y = mx + b$, where $m$ is the slope. Here, $m = -9$.\n\n3. **Find the slope of the perpendicular line:** Lines are perpendicular if their slopes are negative reciprocals. So, if the original slope is $m = -9$, the perpendicular slope $m_\perp$ is $$m_\perp = -\frac{1}{m} = -\frac{1}{-9} = \frac{1}{9}.$$\n\n4. **Write the equation of the perpendicular line:** Using point-slope form $$y - y_1 = m(x - x_1),$$ with point $P(0,0)$ and slope $m_\perp = \frac{1}{9}$, we get $$y - 0 = \frac{1}{9}(x - 0)$$ which simplifies to $$y = \frac{1}{9}x.$$\n\n5. **Final answer:** The equation of the line perpendicular to $$y = -9x - 1$$ passing through $(0,0)$ is $$\boxed{y = \frac{1}{9}x}.$$